Java Collections Interview Question - First Non-Repeating Element

💡 Java Collections Interview Question – Solved Problem: Given an array of integers, find the first non-repeating element using Java Collections. Example Input: [4, 5, 1, 2, 0, 4, 1, 2] Expected Output: 5 Approach: We use a LinkedHashMap because: It maintains insertion order Helps us track frequency while preserving order Java Code: import java.util.*; public class FirstNonRepeating { public static void main(String[] args) { int[] arr = {4, 5, 1, 2, 0, 4, 1, 2}; Map<Integer, Integer> map = new LinkedHashMap<>(); // Count frequency for (int num : arr) { map.put(num, map.getOrDefault(num, 0) + 1); } // Find first non-repeating element for (Map.Entry<Integer, Integer> entry : map.entrySet()) { if (entry.getValue() == 1) { System.out.println("First Non-Repeating Element: " + entry.getKey()); break; } } } } Explanation: Store each element with its count in a LinkedHashMap Iterate through the map The first element with count = 1 is the answer 1. Key Concepts Used: 2. Java Collections Framework 3. LinkedHashMap 4. Hashing & Frequency Count 5. Iteration over Map ✨ Why this matters? This question is frequently asked in interviews to test your understanding of: Collections Time complexity Problem-solving skills #Java #JavaCollections #CodingInterview #DSA #Programming #Developers #Freshers #InterviewPrep

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