Python HackerRank Challenge Day 21

𝗣𝘆𝘁𝗵𝗼𝗻 𝗗𝗮𝗶𝗹𝘆 𝗖𝗵𝗮𝗹𝗹𝗲𝗻𝗴𝗲 | 𝗛𝗮𝗰𝗸𝗲𝗿𝗥𝗮𝗻𝗸 – 𝗰𝗼𝗹𝗹𝗲𝗰𝘁𝗶𝗼𝗻𝘀.𝗖𝗼𝘂𝗻𝘁𝗲𝗿() | 𝗗𝗮𝘆 𝟮𝟯 This Python tool replaces an entire frequency loop. Day 23 of my Python Daily Challenge 🚀 𝗧𝗼𝗱𝗮𝘆’𝘀 𝗽𝗿𝗼𝗯𝗹𝗲𝗺 𝗳𝗲𝗹𝘁 𝗽𝗿𝗮𝗰𝘁𝗶𝗰𝗮𝗹: 👉 Track shoe sizes 👉 Handle multiple customers 👉 Calculate total earnings 𝘠𝘰𝘶 𝘤𝘰𝘶𝘭𝘥 𝘴𝘰𝘭𝘷𝘦 𝘵𝘩𝘪𝘴 𝘸𝘪𝘵𝘩 𝘭𝘰𝘰𝘱𝘴 𝘢𝘯𝘥 𝘥𝘪𝘤𝘵𝘪𝘰𝘯𝘢𝘳𝘪𝘦𝘴… or you could think like Python 👇 𝗧𝗵𝗲 𝗿𝗲𝗮𝗹 𝗶𝗻𝘁𝗲𝗿𝘃𝗶𝗲𝘄 𝗹𝗲𝘀𝘀𝗼𝗻: • Counter handles frequency cleanly • Updates reflect real-world inventory logic • Less code ≠ less clarity 💡 𝗜𝗻𝘁𝗲𝗿𝘃𝗶𝗲𝘄 𝗽𝗮𝘁𝘁𝗲𝗿𝗻 𝗳𝗿𝗼𝗺 𝗗𝗮𝘆 𝟮𝟯: Strong candidates know when to stop reinventing logic and start using the right data structure. That’s how clean, scalable solutions are written. Have you used Counter in real problems before? 👇 #Python #HackerRank #DailyCoding #ProblemSolving #InterviewPrep #LearnInPublic #Consistency

𝗣𝘆𝘁𝗵𝗼𝗻 𝗗𝗮𝗶𝗹𝘆 𝗖𝗵𝗮𝗹𝗹𝗲𝗻𝗴𝗲 | 𝗛𝗮𝗰𝗸𝗲𝗿𝗥𝗮𝗻𝗸 – 𝗶𝘁𝗲𝗿𝘁𝗼𝗼𝗹𝘀.𝗽𝗿𝗼𝗱𝘂𝗰𝘁() | 𝗗𝗮𝘆 𝟮𝟱 Nested loops are optional if you know this. Day 25 of my Python Daily Challenge 🚀 𝗧𝗼𝗱𝗮𝘆’𝘀 𝘁𝗮𝘀𝗸: 👉 Generate all pairs from two lists 👉 Maintain correct order 👉 No missing combinations Most people instantly write nested loops. And yes — that works. But interviews reward awareness, not effort 👇 💡 𝗜𝗻𝘁𝗲𝗿𝘃𝗶𝗲𝘄 𝗽𝗮𝘁𝘁𝗲𝗿𝗻 𝗳𝗿𝗼𝗺 𝗗𝗮𝘆 𝟮𝟱: • Cartesian product is a concept, not just loops • itertools.product() expresses intent clearly • Cleaner code = stronger signal to interviewers Python isn’t about writing more code. It’s about knowing what already exists. Do you still default to nested loops for combinations? 👀 #Python #HackerRank #DailyCoding #ProblemSolving #InterviewPrep #LearnInPublic #Consistency

LeetCode Problem 83: Given the head of a sorted linked list, delete all duplicates such that each element appears only once. Return the linked list sorted as well. The below implementation in Python successfully resolves this in time complexity of O(n) where n is length of the list with constant space complexity. The approach is simple, handle the base case first like list having 0 or 1 number of nodes and then write the logic of handling lists of length greater than one. Maintain two pointers, one to keep track of present node and other to keep track of previous node. Check if the value of both nodes match or not, if match update the pointing of previous node, point its next to the present.next. #LeetCode #LinkedList #Python #CompetitiveProgramming #Algorithms #DataStructures #ProblemSolving

#Projects 🚀 Excited to share my latest project: Thread Shed 🧵✨ https://lnkd.in/gssBsFwy Working with complex string data in Python has always fascinated me. This project was born out of the challenge of handling messy, layered text structures and turning them into something clean, efficient, and insightful. 🔹 Why it matters: Speeds up data parsing and transformation Handles intricate string manipulations with clarity Demonstrates how concurrency can simplify real-world text-heavy workflows 👉 I’d love to hear how others approach complex string challenges in Python. Do you lean on regex, threading, or something else entirely? #Python #Threading #StringProcessing #DataEngineering #Innovation Would you like me to make this post more technical (with code snippets and performance metrics) or more story-driven (focusing on your personal journey and motivation)?

💻 Day (10 and 11): Quick Sort & Array Optimization Today I learned Quick Sort and practiced solving array problems using brute force, better, and optimized approaches. 🔹 Quick Sort • Divide and Conquer algorithm • Uses partitioning around a pivot • Efficient for large datasets (average case) 🔹 Problems Solved: ✅ Largest element in an array ✅ Second largest element in an array (without sorting) ✅ Check if an array is sorted 🧠 Key takeaways: • Optimized solutions reduce unnecessary operations • Thinking in multiple approaches improves problem-solving skills • Understanding time complexity matters as much as writing code #stiversa2zdsasheet #LearningInPublic #DSA #QuickSort #ProblemSolving #Python #rajvikramaditya #leetcode

LeetCode #217 – Contains Duplicate | Python Solution Iterating through nums, each element is checked against a HashSet — if it already exists, return True immediately; otherwise, insert it and continue. No nested loops, no redundant comparisons — just a single pass with instant lookups. 💡 Key Takeaway: Trading space for time is a core algorithmic principle. A set eliminates the need for brute-force O(n²) comparisons by giving constant-time lookups. ⏱ Time: O(n)  💾 Space: O(n) #LeetCode #DataStructures #Python #HashSet #CodingInterview #ProblemSolving #SoftwareEngineering

LeetCode Problem 516: "Longest Palindromic Subsequence": Given a string s, find the longest palindromic subsequence's length in s. A subsequence is a sequence that can be derived from another sequence by deleting some or no elements without changing the order of the remaining elements. The below implementation in Python first reverses the string and then creates a dp array, in which each cell stores the length of longest common subsequence up to the corresponding length of original string and its reversed string. The value at last cell thus contains the length of longest common subsequence for the two strings, since the 2nd string is just reversed of the first one, the common subsequence would be "palindrome". #LeetCode #Python #CompetitiveProgramming #Algorithms #DynamicProgramming #Strings #DataStructures #InterviewPrep #DailyCoding #ProblemSolving

Binary search is a pretty simple algorithm, but it can sometimes cause problems, especially with off-by-one index errors. If possible, we should use the language's built-in methods, for example, `bisect` in Python. However, in some cases, we have to implement it ourselves. While an iterative approach is pretty straightforward, sometimes switching to recursion would produce simpler code. Thus, if we already use additional space, and the call stack won't affect the space complexity, it's reasonable to use recursion. The post: https://lnkd.in/dTttqaCW The problem: https://lnkd.in/dTCzj5Qc #LeetCode #DSATips #DSA #ThinkDSA #ProblemSolving

Developer Releases ai-assert for Runtime Constraint Verification in Local LLMs 📌 ai-assert is a lightweight, dependency-free Python library that enforces output constraints in local LLMs through a smart check → score → retry loop. By validating format, length, and structure in real time, it boosts instruction-following accuracy by up to 6.8 percentage points-rescuing failed prompts and delivering reliable, consistent results without complex setup. 🔗 Read more: https://lnkd.in/d5hbXsqA #Aiassert #Localllms #Pythonlibrary #Runtimeverification

✅ Day 2 of #DSAPrep > Problem: Two Sum > Platform: LeetCode > Concept: HashMap/ Dictionary Used a dictionary to store elements and their indices. For each number, checked whether (target - current number) exists in the map to find the required pair. Optimized the brute-force O(n²) solution to O(n). > Time Complexity: O(n) > Space Complexity: O(n) Accepted ✅ Improving logical thinking and efficiency with every problem. #DataStructures #Algorithms #Python #ProblemSolving #CodingJourney