How to Convert Sorted Array to Balanced BST in 30 Days

🚀 Day 7 of Educative’s 30-Day Coding Challenge 🧩 Problem: Convert Sorted Array to Binary Search Tree 💡 Approach: 🔹 Use a divide-and-conquer strategy to maintain BST balance. 🔹 Choose the middle element of the current subarray as the root node. 🔹 Recursively build the left subtree from the left half and the right subtree from the right half. 🔹 Base case: when left > right, return null. 🎯 Takeaway: Balanced trees are all about symmetry and structure — a great reminder that the right balance can make any system efficient and scalable. 🌱 #30DaysofCode #Educative Educative #CodingChallenge #Consistency #Java #ProblemSolving

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