Java Main Method: Entry Point for JVM Execution

Understanding the Java "main()" Method — "public static void main(String[] args)" Every Java program starts execution from the main() method. When you run a Java program, the JVM (Java Virtual Machine) looks for this method as the entry point. If a program does not contain a valid "main()" method, the JVM will not start execution. The commonly used syntax is: public static void main(String[] args) Each word in this declaration has a specific purpose: • public → Access modifier that allows the JVM to call the method from outside the class. If it is not public, the JVM cannot access it. • static → Allows the method to be called without creating an object of the class. The JVM can directly invoke the method when the program starts. • void → Specifies that the method does not return any value. Once the main method finishes execution, the Java program terminates. • main → The method name recognized by the JVM as the starting point of the program. Changing this name prevents the program from running. • String[] args → An array that stores command-line arguments passed when running the program. Example: class Example { public static void main(String[] args) { System.out.println("Hello, Java!"); } } Java also allows equivalent forms like: public static void main(String args[]) public static void main(String... args) All of these work because the parameter is still treated as a String array. Key Takeaway: The "main()" method acts as the entry point of a Java application, allowing the JVM to begin executing the program. #Java #JavaProgramming #CoreJava #JVM #BackendDevelopment #Programming #LearnToCode

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