Greedy Scheduling Solution for Minimum Machines

🚀 [Day 13/30] Coding Challenge with @Educative.io 💻 💡 Problem: Schedule Tasks on Minimum Machines Today’s challenge was a classic interval scheduling problem — determining the minimum number of machines needed so that no tasks running on the same machine overlap. The moment I read the problem, I realized this was a greedy + sorting problem. My approach: 1️⃣ Sort all tasks by start time 2️⃣ Assign tasks to the current machine as long as they don’t overlap 3️⃣ Move overlapping tasks to a separate list for the next iteration (next machine) 4️⃣ Repeat this process until all tasks are assigned Each iteration represents one machine, so the number of iterations gives the minimum machines needed. ✨ Small win: Visualizing machines as “layers” of non-overlapping tasks made the greedy logic very intuitive. 🔍 Key Learnings: Sorting intervals is the first step in almost every scheduling problem Greedy allocation simplifies resource management problems Separating overlapping vs non-overlapping tasks reveals the minimum number of resources needed #30DaysOfCode #Day13 #CodingChallenge #Educative #DSA #Greedy #Scheduling #Intervals #JavaScript #ProblemSolving #InterviewPrep #SoftwareEngineer #LearningInPublic #TechCareers #KeepCoding

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