"Optimized Subarray Counting with Sliding Window Logic"

🚀 [Day 12/30] Coding Challenge Journey with @Educative.io 💻 💡 Problem: Count Subarrays With Fixed Bounds Today’s challenge really tested my understanding of subarray patterns and sliding window logic. The task was to count all subarrays where the minimum and maximum values are exactly equal to given bounds — minK and maxK. At first, my approach was brute force — I generated all possible subarrays, calculated the min and max for each, and increased the count if they matched. It worked, but with a painful O(n² + n) time complexity 😅 Then came the optimization breakthrough 💡 — I introduced three variables: badIndex → to mark positions where elements go out of range minIndex and maxIndex → to store the latest positions of valid min and max For each element, if it stayed within bounds, I could efficiently calculate how many valid subarrays ended at that index by using: count += Math.max(0, Math.min(minIndex, maxIndex) - badIndex) This reduced the complexity to O(n) and turned an expensive brute force into a clean, efficient linear pass ⚡ 🔍 Key Learnings: Identifying invalid states early (like badIndex) saves massive computation. Most subarray problems can be optimized using index tracking instead of recalculating repeatedly. Optimization isn’t about writing less code — it’s about thinking one step deeper 🧠 ✨ Small win — seeing how a few well-chosen variables can simplify a seemingly complex logic! #30DaysOfCode #Day12 #CodingChallenge #DSA #Educative #ProblemSolving #JavaScript #SlidingWindow #Optimization #KeepCoding #LearningJourney #Subarrays

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