Learn Big-O Complexity with this Cheat Sheet for Interviews

Tree traversal is the most common and basic set of algorithms you should know to prepare for a technical interview. However, I still learn something new, for example, in-order Morris traversal, which doesn't use any additional space. It was hard to understand this specific problem because it used a bit more complex logic with steps and levels, but it's a pretty interesting approach that I would like to master. The post: https://lnkd.in/dV-ftESW The problem: https://lnkd.in/dWDWVsNA #LeetCode #DSATips #DSA #ThinkDSA #ProblemSolving

𝗧𝗼𝗱𝗮𝘆'𝘀 𝗟𝗲𝗲𝘁𝗖𝗼𝗱𝗲 𝗗𝗮𝗶𝗹𝘆 𝗖𝗵𝗮𝗹𝗹𝗲𝗻𝗴𝗲 𝗦𝗼𝗹𝘂𝘁𝗶𝗼𝗻 (𝟯𝟮𝟭𝟳. 𝗗𝗲𝗹𝗲𝘁𝗲 𝗡𝗼𝗱𝗲𝘀 𝗙𝗿𝗼𝗺 𝗟𝗶𝗻𝗸𝗲𝗱 𝗟𝗶𝘀𝘁 𝗣𝗿𝗲𝘀𝗲𝗻𝘁 𝗶𝗻 𝗔𝗿𝗿𝗮𝘆) The idea behind this solution is to remove all nodes from the linked list whose values are present in the given array nums. To do this efficiently, the algorithm first stores all values from nums in an unordered_set for O(1) lookup time. Then, it skips all leading nodes in the list whose values exist in this set, thereby finding the correct new head of the modified list. After establishing the new head, it traverses the rest of the list using a pointer curr; whenever the next node’s value is found in the set, that node is bypassed by linking curr->next to curr->next->next. Otherwise, the traversal continues normally. #LeetCode #DSA #ProblemSolving #Motivation #Consistency #Interview #DailyChallenge

Top 50 Technical Interview Q&A Getting ready for your next technical interview? This guide is packed with the most frequently asked questions across core programming, web development, databases, and problem-solving everything you need to level up your prep! Ace your interviews with confidence and get one step closer to your dream job! 🔁 Repost & Share with others to help them upskill! 📢 Follow Sakshi Singh Kushwaha for more such content. #InterviewPreparation #TechnicalInterview #CodingInterview

𝗧𝗼𝗱𝗮𝘆'𝘀 𝗟𝗲𝗲𝘁𝗖𝗼𝗱𝗲 𝗗𝗮𝗶𝗹𝘆 𝗖𝗵𝗮𝗹𝗹𝗲𝗻𝗴𝗲 𝗦𝗼𝗹𝘂𝘁𝗶𝗼𝗻 (𝟮𝟱𝟯𝟲. 𝗜𝗻𝗰𝗿𝗲𝗺𝗲𝗻𝘁 𝗦𝘂𝗯𝗺𝗮𝘁𝗿𝗶𝗰𝗲𝘀 𝗯𝘆 𝗢𝗻𝗲) 𝗦𝗼𝗹𝘂𝘁𝗶𝗼𝗻 𝗟𝗶𝗻𝗸 : https://lnkd.in/dFi-34Sn 𝗗𝗶𝗳𝗳𝗶𝗰𝘂𝗹𝘁𝘆 : 𝗠𝗲𝗱𝗶𝘂𝗺 You're using a 2D difference matrix to perform range updates efficiently. Instead of adding 1 to every cell inside each query’s rectangle (which would be slow), you mark only the rectangle boundaries in a smart way: add +1 at the top-left corner to start increasing, add -1 just outside the right and bottom edges to stop the increase, and add +1 at the bottom-right outside cell to fix overlap. After processing all queries this way, you take a prefix sum row-wise and then column-wise, which propagates these boundary changes across the matrix. #LeetCode #DailyChallenge #DSA #ProblemSolving #Motivation #Consistency #Interview

𝗧𝗼𝗱𝗮𝘆'𝘀 𝗟𝗲𝗲𝘁𝗖𝗼𝗱𝗲 𝗗𝗮𝗶𝗹𝘆 𝗖𝗵𝗮𝗹𝗹𝗲𝗻𝗴𝗲 𝗦𝗼𝗹𝘂𝘁𝗶𝗼𝗻 (𝟯𝟱𝟰𝟮. 𝗠𝗶𝗻𝗶𝗺𝘂𝗺 𝗢𝗽𝗲𝗿𝗮𝘁𝗶𝗼𝗻𝘀 𝘁𝗼 𝗖𝗼𝗻𝘃𝗲𝗿𝘁 𝗔𝗹𝗹 𝗘𝗹𝗲𝗺𝗲𝗻𝘁𝘀 𝘁𝗼 𝗭𝗲𝗿𝗼) 𝗗𝗶𝗳𝗳𝗶𝗰𝘂𝗹𝘁𝘆 : 𝗠𝗲𝗱𝗶𝘂𝗺 𝗦𝗼𝗹𝘂𝘁𝗶𝗼𝗻 𝗟𝗶𝗻𝗸 : https://lnkd.in/dygC_DGm The idea is to count how many distinct “increasing layers” of positive values appear as we scan from left to right. Each operation can remove all occurrences of a specific positive value (the minimum in some chosen subarray), so effectively you want to know how many times a new positive “height” begins that cannot be removed together with previous ones. The stack keeps track of the current active increasing sequence of values: if the current number is smaller than the top, we pop because those larger numbers will be eliminated earlier; if it’s greater than the top (or the stack is empty), it represents a new layer of value that will need its own operation, so we increment the answer and push it. By doing this for the whole array, we count exactly how many independent positive layers exist - that’s the minimum number of operations required. #LeetCode #DailyChallenge #DSA #ProblemSolving #Motivation #Consistency #Interview

QUORUM — explained in 30 seconds 💡 Definition: Quorum = the minimum number of replicas that must agree before a read or write is accepted as valid. 🧪 Example: You have 5 replicas. If 3 confirm “saved ✅”, the system marks the write successful. That “3 of 5” is the quorum. ⚙️ Why it matters: ✅ Faster responses — you don’t wait for every replica 🔁 Higher availability — system works even if some nodes are down 🔒 Trustworthy results — multiple copies agree 🗣️ Interview line: “Quorum is the minimum number of replicas that must agree before we trust the operation. For example, if 3 of 5 replicas confirm a write, it’s accepted.” 👇 Save this for your next interview. Follow The Prep Circuit for plain-English tech prep ⚡ . . . . . . . . . #ThePrepCircuit #interviewprep #systemdesign #distributedSystems #databases #consistency #availability #replication #scalability #backend #techinterview

Asyncio: Interview Questions and Practice Problems In this article, we will go through some of the most commonly asked practice problems and interview questions related to asyncio. import asyncio import aiohttp async def fetch_url(session, url): async with session.get(url) as response: return await response.text() async def main(): ... https://lnkd.in/eeDvzbVQ By Sushant Gaurav

Forget resumes. Take them out for dinner. Watch how they treat the server. That’s the real interview. Inspo: Blaine Davis

This new guide will help you learn how to answer common REST API interview questions covering both fundamental and intermediate topics. By Ekene Eze https://lnkd.in/gFj44iMT