Deci-Binary Numbers: Min Partitions Solution

🚀 Day 51 of #100DaysOfCode ✅ Solved: 1689. Partitioning Into Minimum Number of Deci-Binary Numbers Today’s problem looked tricky at first, but the solution turned out to be beautifully simple once the pattern was understood. 🔎 Problem Insight: A deci-binary number contains only digits 0 or 1. To form a number like "82734", think about each digit: If a digit is 8, we need at least 8 deci-binary numbers contributing 1 at that position. If a digit is 3, we need at least 3 deci-binary numbers at that position. 👉 So the minimum number of deci-binary numbers required is simply: 📌 The maximum digit in the given number 💡 Example: Input: "82734" Output: 8 🧠 Python Code: Python Copy code class Solution: def minPartitions(self, n: str) -> int: return int(max(n)) ⏱ Time Complexity: O(N) 💾 Space Complexity: O(1) This problem is a great example of how understanding the pattern simplifies the solution dramatically. #LeetCode #ProblemSolving #Python #DataStructures #CodingJourney #100DaysOfCode

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