Divide Array into Subarrays with Min Cost: LeetCode 3010 Solution

🚀 Day 27 of #100DaysOfCode Today’s problem: LeetCode 3010 – Divide an Array Into Subarrays With Minimum Cost I At first glance, it felt like a DP problem. But after breaking it down, the solution turned out to be simple and elegant. 🧠 Key Insight: Split the array into 3 contiguous subarrays Cost of a subarray = its first element First subarray always starts at index 0 To minimize cost → pick the two smallest elements from the remaining array ✅ Python Solution: Copy code Python class Solution: def minimumCost(self, nums: list[int]) -> int: return nums[0] + sum(sorted(nums[1:])[:2]) 💡 Learning: Don’t jump to complex solutions too quickly. Sometimes, the optimal answer comes from understanding the problem constraints deeply. 📈 Staying consistent, one problem at a time. #100DaysOfCode #Day27 #LeetCode #Python #DSA #ProblemSolving #Consistency #LearningInPublic #Learning

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