Day 31- What I Learned In a Day(JAVA) Today, I learned about nested for loops and how they are used in pattern programming. A nested loop is simply a loop inside another loop. The outer loop controls the number of rows, while the inner loop controls what gets printed in each row (columns). 🔹 Outer loop → runs row by row 🔹 Inner loop → runs completely for each row 🔹 This helps in creating patterns like squares, triangles, and pyramids For every single iteration of the outer loop, the inner loop executes fully this is the key idea behind pattern problems. Understanding this concept improved my ability to break down problems step by step and visualize output clearly. I Practiced 16 Patterns 👇 #Java #Programming #Coding #LearningJourney #NestedLoops #PatternProgramming
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🚀 Code 3 – #50LeetCodeChallenge Problem: 4Sum Given an array of integers and a target value, find all unique quadruplets that sum up to the target. Each element must be used only once, and the solution set should not contain duplicate combinations. 💡 Approach: Sort the array and use nested loops along with a two-pointer technique to find combinations efficiently. Skip duplicate elements to ensure only unique quadruplets are included. 📚 Key Takeaway: Combining sorting with the two-pointer approach helps reduce complexity and is highly effective for solving multi-sum problems like 4Sum. #LeetCode #Java #Coding #ProblemSolving #Arrays #TwoPointers #Programming
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🚀 Code 2 – #50LeetCodeChallenge Problem: "Longest Common Prefix" Given an array of strings, find the longest common prefix shared among all strings. If no common prefix exists, return an empty string "". 💡 Approach: Start with the first string as the prefix and compare it with the remaining strings. Gradually reduce the prefix until it matches the beginning of each string. 📚 Key Takeaway: String comparison and iterative reduction help efficiently solve prefix-based problems with optimal performance. #LeetCode #Java #Coding #ProblemSolving #Strings #Programming
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🚀 Code 5– #50LeetCodeChallenge 🧩 Problem: Remove Element Given an array and a value val, remove all occurrences of val in-place and return the count of remaining elements. The order of elements can be changed. 💡 Approach: Use a two-pointer technique—one pointer iterates through the array, while the other keeps track of the position to place elements that are not equal to val. 📚 Key Takeaway: In-place modification with two pointers helps achieve O(n) time complexity and O(1) space, making it efficient for array filtering problems. #LeetCode #Java #Coding #ProblemSolving #Arrays #TwoPointers #Programming
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🚀 Code 6 – #50LeetCodeChallenge 🧩 Problem: Search Insert Position Given a sorted array of distinct integers and a target value, return its index if found. If not, return the position where it should be inserted to maintain sorted order. 💡 Approach: Use Binary Search to efficiently locate the target or its correct insertion position in O(log n) time. 📚 Key Takeaway: Binary search is the go-to technique for problems involving sorted arrays, especially when optimal time complexity is required. #LeetCode #Java #Coding #ProblemSolving #BinarySearch #Arrays #Programming
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🚀 Code 4 – #50LeetCodeChallenge 🧩 Problem: Remove Duplicates from Sorted Array Given a sorted array, remove duplicates in-place so that each unique element appears only once. Return the count of unique elements while maintaining the original order. 💡 Approach: Use the two-pointer technique—one pointer tracks the position of unique elements, while the other scans through the array. When a new unique element is found, place it at the correct position. 📚 Key Takeaway: Two-pointer approach is highly efficient for in-place array modifications, reducing space complexity to O(1) and time complexity to O(n). #LeetCode #Java #Coding #ProblemSolving #Arrays #TwoPointers #Programming
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🔹 Reverse Number in Java – Logic + Implementation Strong fundamentals are key to becoming a better developer. This example demonstrates how to reverse a number using simple mathematical operations: • Extract last digit using modulus (%) • Build the reversed number step by step • Reduce the number using division (/) Such problems help improve logical thinking and coding efficiency. 🎥 I’ve also created a short video explaining this concept with code: YouTube link : https://lnkd.in/gfaafZWZ #Java #Programming #ProblemSolving #Coding #SoftwareDevelopment #Learning
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Sum of the Array in Java | Easy Logic + Coding 💡 Strong fundamentals are the key to mastering programming. This example shows how to find the sum of array elements using simple logic: • Start with an array of numbers • Initialize a sum variable to 0 • Traverse the array using a loop • Add each element to the sum • Print the final result Practicing these basic problems helps build strong logical thinking and coding confidence. 📊 Example Input : [1, 2, 3, 4] Output : 10 🎥 I’ve also created a short video explaining this concept with code: YouTube link : https://lnkd.in/g9SJ3hvJ #Java #Programming #ProblemSolving #Coding #SoftwareDevelopment #Learning #CSE #Developers #LogicBuilding #Arrays
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🚀 Day 23 of My /Java Programming Journey Today I learned about Command Line Arguments — a powerful way to pass inputs directly while running a program 💻 🔹 No need for Scanner input 🔹 Inputs are passed at runtime 🔹 Stored in "String[] args" 🔹 Makes programs faster & more flexible 💡 Example: Run → "java Program 10 20" Output → Uses these values inside the code This concept helped me understand how real-world programs take dynamic input efficiently ⚡ 📌 Key Takeaway: Command line arguments make your program more dynamic and professional #Programming #Java #CProgramming #CodingJourney #100DaysOfCode #DeveloperLife #Learning #Tech #CodeNewbie #SoftwareEngineering
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Turning simple logic into working code 💻✨ Today I worked on a basic yet essential problem in Java—finding the maximum value in an array. It’s one of those foundational exercises that really strengthens your understanding of loops, arrays, and conditionals. 🔹 Took user input using Scanner 🔹 Stored values in an array 🔹 Iterated to find the maximum element What seems simple at first actually builds the backbone of problem-solving skills in programming. Every small step counts in the journey of becoming a better developer 🚀 #Java #CodingJourney #Programming #ProblemSolving #LearningByDoing
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📌 Understanding the Fundamentals of Java For Loop A for loop is one of the most powerful control structures used for iteration. It operates based on three key components: 1️⃣ Initialization – Defines the starting point 2️⃣ Condition – Determines when the loop should stop 3️⃣ Step (Update) – Controls how the loop progresses 🔄 Execution Flow: Initialization → Condition → Execute → Step → Repeat 📈 Types of Iteration: • Forward Loop → Increment (i++) → Example: 1 to 9 • Backward Loop → Decrement (i--) → Example: 9 to 1 💡 Key Insight: A for loop is essentially movement across a number line with a defined start, end, and step. This simple visualization helps in understanding: ✔ Loop control ✔ Iteration logic ✔ Avoiding infinite loops #Java #SoftwareDevelopment #Programming #Coding #TechLearning
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