Understanding closures and variable scoping is what separates a good Python developer from a great one. 💻 In this video, I break down the "Late Binding" behavior in Python lambdas. It’s a common pitfall when creating functions inside loops, leading to bugs that are incredibly hard to track down in large codebases. Key Takeaway: Default arguments are evaluated at definition time, but closures capture variables by reference. To fix this, we use the i=i trick to force early binding. Have you ever encountered this "Late Binding" bug in your production code? #PythonProgramming #SoftwareDevelopment #CleanCode #ComputerScience #TechEducation #BackendDeveloper
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Here's a Python dictionary merge challenge from @dontmisstmr — can you get it right without running the code? dict1 = {"name": "Alice", "age": 25} dict2 = {"city": "Noida", "age": 26} merged = dict1 | dict2 print(merged) The | operator was introduced in Python 3.9. When both dicts share a key, which value wins? Drop your answer in the comments! #Python #SoftwareDevelopment #CodingChallenge #ProgrammingTips #TechCommunity
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Cool new blog post: why async Python is secretly deterministic. We dive into how the Python event loop really works and show that even though async tasks may interleave, they always start execution in a predictable order, making it easier to build concurrent async workflows.
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Learn how to create a chatbot with Python and Dialogflow, including step-by-step guide, advanced features, and real-world applications, with a focus on creating a chatbot with Python https://lnkd.in/g8GFzcvs #CreateChatbotWithPython Read the full article https://lnkd.in/g8GFzcvs
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Learn how to create a chatbot with Python and Dialogflow, including step-by-step guide, advanced features, and real-world applications, with a focus on creating a chatbot with Python https://lnkd.in/g8GFzcvs #CreateChatbotWithPython Read the full article https://lnkd.in/g8GFzcvs
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Day 38/100 – #100DaysOfCode 🚀 Solved LeetCode #2011 – Final Value of Variable After Performing Operations (Python). Today I practiced string handling and simple iteration to compute the final value after a series of operations. Approach: 1) Initialize a variable x = 0. 2) Traverse through each operation in the list. 3) If the operation contains "++", increment x by 1. 4) Otherwise, decrement x by 1. 5) Return the final value of x. Time Complexity: O(n) Space Complexity: O(1) Simple logic but great practice for handling strings and loops 💪 #LeetCode #Python #DSA #Strings #ProblemSolving #100DaysOfCode
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🚀 Day 2 — Python Journey Continuing with Python, today I focused on integer operations. 📌 What I learned: - Integer declaration - Addition, subtraction, multiplication - Division and modulus (remainder) - Power operation - Operator precedence (which operation runs first) 💡 What stood out: Understanding operator precedence is really important — the same expression can give different results if you don’t know the order of execution. Also, modulus (%) is more useful than it looks (especially for problems and logic building). Trying to stay consistent and build strong basics step by step. #Day2 #Python #CodingJourney #Consistency #LearnInPublic
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Day 46/100 – #100DaysOfCode 🚀 Solved LeetCode #2733 – Neither Minimum nor Maximum (Python). Today I practiced sorting and simple array logic to find any element that is neither the minimum nor the maximum in the array. Approach: 1) Sort the array. 2) Check the length of the array. 3) If the size is less than or equal to 2, return -1 (no valid element exists). 4) Otherwise, return the second element as it will be neither min nor max. Time Complexity: O(n log n) Space Complexity: O(1) Understanding how sorting simplifies boundary-based problems 💪 #LeetCode #Python #DSA #Arrays #Sorting #ProblemSolving #100DaysOfCode
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Day 50/100 – #100DaysOfCode 🚀 Solved LeetCode #28 – Find the Index of the First Occurrence in a String (Python). Today I practiced string matching using a brute-force approach to find the first occurrence of a substring. Approach: 1) Traverse the main string (haystack). 2) For each index, try to match the substring (needle). 3) Compare characters one by one. 4) If all characters match, return the starting index. 5) If mismatch occurs, break and move to the next index. 6) If no match is found, return -1. Time Complexity: O(n × m) Space Complexity: O(1) Understanding basic string matching techniques step by step 💪 #LeetCode #Python #DSA #Strings #ProblemSolving #100DaysOfCode
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Here's a quick Python tuple unpacking challenge from @dontmisstmr — can you get it right without running the code? nums = (10, 20, 30, (40, 50, 60)) x, y, z, nested = nums a, b, c = nested print(f"{z} and {b}") Tuple unpacking is one of those Python features that looks simple but trips people up the moment nesting gets involved. Drop your answer in the comments — and if you got it wrong, what threw you off? #Python #SoftwareDevelopment #CodingChallenge #ProgrammingTips #TechCommunity
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Ran a 1 billion nested loop iteration test using the Fibonacci sequence across C, Rust, Go and Python. Expected results, but still interesting to see the actual numbers. C and Rust came in at 0.32s. Go at 0.84s. Python timed out after 10 minutes so we just won't talk about that. The C and Rust parity makes sense, both compile down to highly optimized machine code. Go has a runtime and a garbage collector, so that gap is expected. Python is a different category of language entirely. It's not built for this and that's fine, it's just not what you reach for when raw compute speed matters.
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