3Sum LeetCode Solution with Efficient Sorting and Two-Pointer Technique

🚀 LeetCode: 3Sum The goal is to find all unique triplets in an array that sum up to zero. This is a significant step up from Two Sum, requiring careful handling of duplicates to ensure every triplet in the result is unique. 🛠️ My Approach Sorting for Strategy: I started by sorting the array in ascending order. This is crucial as it allows us to easily skip duplicate values and use a directional two-pointer technique. 🔡 Fixed Element Loop: I iterated through the array, treating each element as a potential first part of a triplet. To optimize, if the current element is greater than zero, I break the loop immediately since no combination of following positive numbers can sum to zero. 🧹 Two-Pointer Optimization: For each fixed element, I used two pointers—one starting just after the fixed element (l) and one at the very end (r). 📍 If the sum is too high, I move the right pointer in. If the sum is too low, I move the left pointer out. When a sum of zero is found, I capture the triplet and then skip any identical adjacent values to avoid duplicate results. ❌ This approach transforms a potential O(n^3) brute-force cubic time complexity into a much more efficient quadratic solution. 📊 Efficiency Analysis ⏱️ Time Complexity: O(n^2) due to the nested two-pointer search inside the main loop. 💾 Space Complexity: O(1) or O(n) depending on the implementation of the sorting algorithm, as we don't use extra data structures for the search itself. Achieving a 91.76% runtime beat on this classic problem! Handling edge cases and duplicates is where the real engineering happens. 🚀👨💻 #LeetCode #JavaScript #CodingLife #Algorithms #WebDevelopment #ProblemSolving #SoftwareEngineering #TechCommunity

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