Java HashMap Collision Handling and Optimization

#Post1 Internal working of HashMap And Hash collision 👇 When we insert a value: map.put("Apple", 10) Java performs these steps: 1️⃣ It calls hashCode() on the key. For example, Strings generate hash codes using a formula involving the prime number 31. 2️⃣ Using this hash, Java calculates the bucket index inside the internal array. Now the entry is stored inside that bucket. Example internal structure: Bucket Array [0] [1] [2] → (Apple,10) [3] [4] But what if two keys map to the same bucket? This situation is called a hash collision. Example: [2] → (Apple,10) → (Banana,20) → (Mango,30) HashMap handles collisions by storing multiple entries inside the same bucket. Before Java 8 • Entries were stored in a Linked List After Java 8 • If the bucket size grows beyond 8, the linked list is converted into a Red-Black Tree This improves search performance: O(n) → O(log n) Now let’s see what happens during get() when a bucket has multiple entries. When we call: map.get("Apple") Java performs these steps: 1️⃣ It recomputes the hashCode() of the key 2️⃣ It finds the same bucket index using (capacity - 1) & hash 3️⃣ If multiple nodes exist in that bucket, Java traverses the nodes For each node it checks: existingNode.hash == hash AND existingNode.key.equals(key) Once the correct key is found, the corresponding value is returned. Summary: Two different keys can generate the same hash, which causes a hash collision. HashMap handles collisions by storing entries as a Linked List or Red-Black Tree inside the bucket. 📌 Note HashMap is not thread safe. In the upcoming post, we will explore the thread-safe alternative to HashMap. #Java #SoftwareEngineering #BackendDevelopment #DataStructures #Programming #LearnInPublic

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