Solving LeetCode 'Divide Two Integers' in Java

🚀 Day 7/30 — LeetCode Challenge Solved "Roman to Integer" on LeetCode using Java. The key challenge was handling "subtractive notation"— cases like IV (4) and IX (9), where a smaller value appears before a larger one. Used a HashMap for value mapping and adjusted the result based on the relationship between adjacent characters. ✅ Key takeaway: Understanding patterns in rules is more important than just implementing logic. #LeetCode #Java #Algorithms #ProblemSolving #Consistency

🚀 Day 4/30 — LeetCode Challenge Solved the "Palindrome Number" problem on LeetCode using Java. The logic is simple, but the key is choosing the right approach — reversing only half of the number instead of the entire value to avoid unnecessary operations. ✅ Key takeaway: Even simple problems have smarter solutions if you focus on efficiency. Continuing to build consistency and improve problem-solving skills. #LeetCode #Java #Algorithms #ProblemSolving #Consistency

🚀 Day 2/30 — LeetCode Challenge Solved the Reverse Integer problem on using Java. At first glance, reversing digits looks straightforward. But the real challenge is handling integer overflow within 32-bit limits — that’s where most implementations fail. ✅ Key takeaway: Correctness isn’t just about logic — it’s about respecting constraints and edge cases. Continuing to focus on writing solutions that are not just working, but reliable. #LeetCode #Java #ProblemSolving #DataStructures #Algorithms #Consistency

🚀 Day 8/30 — LeetCode Challenge Solved "Swap Nodes in Pairs" on LeetCode using Java. This problem focuses on "rearranging node connections", not just swapping values — making pointer handling critical. Used a dummy node approach to simplify edge cases and ensure smooth pair-wise swapping. ✅ Key takeaway: Linked list problems are less about logic and more about **precise pointer management** — one wrong link can break the entire structure. #LeetCode #Java #LinkedList #DataStructures #ProblemSolving #Consistency

Day 22 of #50DaysLeetCode Challenge 🚀 Today I solved the “Remove Element” problem using Java. 🔹 Problem: Given an array and a value, remove all occurrences of that value in-place and return the number of remaining elements. 🔹 Approach: Used the two-pointer technique. One pointer iterates through the array, while the other keeps track of where to place elements that are not equal to the given value. 🔹 Key Learning: In-place array problems often rely on pointer manipulation instead of extra space. 🔹 Time Complexity: O(n) 🔹 Example: Input: nums = [3,2,2,3], val = 3 Output: 2 (array becomes [2,2,...]) Simple problem, but important for mastering array manipulation techniques. #Day22 #LeetCode #Java #DSA #Arrays #TwoPointers #CodingJourney #ProblemSolving

🚀 Day 3/30 — LeetCode Challenge Solved Median of Two Sorted Arrays on using Java. This wasn’t about merging arrays — the real challenge was applying binary search on partitions to achieve optimal time complexity. ✅ Key takeaway: Efficiency comes from thinking differently, not doing more work. Using partition-based binary search reduces complexity to O(log(min(n, m))). This problem pushed me to understand the logic deeply rather than just implementing it. #LeetCode #Java #Algorithms #BinarySearch #ProblemSolving #Consistency Archana J E Divya Suresh Harini B harilakshmi s Bavani k Bhavya B Devipriya R

🚀 Day 47/180 | #180DaysOfCode 📍 LeetCode | 💻 Java Solved: 448. Find All Numbers Disappeared in an Array Used an in-place marking technique by treating indices as a hash map and marking visited numbers as negative to identify missing elements. ⏱️ Time Complexity: O(n) 📦 Space Complexity: O(1) (excluding output list) Strengthening understanding of array manipulation and in-place hashing tricks. 💪 Consistency continues 🚀 #DSA #LeetCode #Java #CodingJourney #Consistency

Day 94 - LeetCode Journey Solved LeetCode 35: Search Insert Position in Java ✅ Classic Binary Search problem that tests your fundamentals. Instead of just finding the element, the twist is to return the correct insert position if it’s not present. The key idea is simple: keep narrowing the search space and finally return low, which represents the right position. Clean logic, high impact 💡 Key takeaways: • Strong grip on Binary Search fundamentals • Understanding search space boundaries • Returning correct insertion index • Writing efficient O(log n) solutions ✅ All test cases passed ⚡ O(log n) time and O(1) space Mastering basics like Binary Search is what builds real problem-solving strength 🔥 #LeetCode #DSA #Java #BinarySearch #ProblemSolving #CodingJourney #InterviewPrep #Consistency #100DaysOfCode

🚀 Day 57/180 | #180DaysOfCode 📍 LeetCode | 💻 Java Solved: 242. Valid Anagram Used a HashMap frequency counting approach (Unicode-safe using code points) to compare character frequencies of both strings. ⏱️ Time Complexity: O(n) 📦 Space Complexity: O(n) Strengthening understanding of string frequency analysis and Unicode handling. 💪 Consistency continues 🚀 #DSA #LeetCode #Java #CodingJourney #Consistency