Gray Code Generation in C++ with Bit Manipulation

Solved a Gray Code problem in C++ today. The task was to generate bit patterns from 0 to 2^n - 1 such that every consecutive pattern differs by only one bit, while always starting from 0. I used the Gray code formula: gray = i ^ (i >> 1) This makes the solution clean and efficient, and guarantees that adjacent codes differ by exactly one bit. Example for n = 2: 00 -> 01 -> 11 -> 10 What I like about this problem is how a simple bit manipulation formula can solve what looks like a complex sequence-generation challenge. Concepts practiced: Bit Manipulation Binary Representation Pattern Generation C++ Problem Solving #cpp #coding #programming #datastructures #algorithms #problemsolving #bitmanipulation #leetcode #geekforgeeks

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