Aymen FARHANI’s Post

#Java #SpringBoot #SpringWeb #RestTemplate 𝗛𝗼𝘄 𝘁𝗼 𝗺𝗮𝗸𝗲 𝗥𝗲𝘀𝘁𝗧𝗲𝗺𝗽𝗹𝗮𝘁𝗲 𝗿𝗲𝘁𝘂𝗿𝗻 𝗮 𝗟𝗶𝘀𝘁<𝗬𝗼𝘂𝗿𝗧𝘆𝗽𝗲> When you request a single object with RestTemplate, mapping is straightforward. Returning a List<T> is trickier because of Java’s type erasure at runtime List<Foo> looks like List.  Spring’s RestTemplate needs help to know the concrete element type so Jackson (or another HttpMessageConverter) can deserialize JSON into List<YourType>. 𝗪𝗵𝘆 𝗶𝘁’𝘀 𝘁𝗿𝗶𝗰𝗸𝘆 Java generics are erased at runtime. A List<Student> and a List<Object> are both just List to the JVM.  RestTemplate and Jackson therefore cannot automatically deduce the T in List<T>. You must provide explicit type information when you want a typed list response. 𝗥𝗲𝗰𝗼𝗺𝗺𝗲𝗻𝗱𝗲𝗱 𝗦𝗼𝗹𝘂𝘁𝗶𝗼𝗻: exchange() + ParameterizedTypeReference This is the most common, type-safe approach: ResponseEntity<List<Enrollment>> response = restTemplate.exchange(   "http://localhost:8082/api/v1/enrollments/{studentId}",   HttpMethod.GET,   null, // or new HttpEntity<>(headers)   new ParameterizedTypeReference<List<Enrollment>>() {},   studentId ); List<Enrollment> enrollments = response.getBody(); where restTemplate is a bean in a configuration class: @Bean public RestTemplate restTemplate() {   return new RestTemplate(); } 𝗡𝗼𝘁𝗲𝘀: - ParameterizedTypeReference<List<Enrollment>>() {} is an anonymous subclass that preserves the generic type info at runtime for Spring to use. - You can pass headers via HttpEntity<T> if you need Accept or authorization headers. 𝗧𝗵𝗲𝗿𝗲 𝗶𝘀 𝗮𝗻𝗼𝘁𝗵𝗲𝗿 𝘀𝗼𝗹𝘂𝘁𝗶𝗼𝗻: Request an array YourType[] (getForObject(..., YourType[].class)) and convert with Arrays.asList(...)

  • graphical user interface, application

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