Map vs Multimap: Understanding find() and count() in C++

In C++, a single-argument constructor can allow implicit type conversion, which may lead to unexpected behavior. Using the explicit keyword prevents automatic conversions and makes object creation intentional. It improves code safety and clarity. Modern C++ strongly recommends marking single-parameter constructors as explicit. Small keyword. Big safety improvement. #cpp #moderncpp #softwareengineering #programming

what is the output of this code snippet? #include<stdio.h> void main() { int a[5]={10,20,30,40}; char *p[3]={a+2,a+1,a}; short int **q=p+1; ++*q; printf("%d\n",q[1][1]); printf("%d\n",q[0][-1]); } #cprogramming #embeddedc #pointers #c

LeetCode Daily – #1784 Check if Binary String Has at Most One Segment of Ones [Easy] The Insight: Since the string always starts with '1' (no leading zeros), the only way a second segment of ones can appear is if a '0' comes BEFORE another '1' — i.e., the substring "01" exists in the string. So the entire problem reduces to one check: → Does "01" appear in the string? If yes → false. If no → true. Time: O(N) | Space: O(1) This is one of those problems where stripping away the noise leads to an almost trivially elegant solution. The key was recognizing the constraint — no leading zeros — which guarantees the string always opens with a '1', making "01" the only possible signal of a broken segment. Sometimes the best code is the code you don't write. 🚀 #LeetCode #CodingChallenge #CPlusPlus #ProblemSolving #Programming #SoftwareEngineering #POTD #DSA

Your static initializer logic could silently break your class. You define a static property that depends on another static property declared later. Then you log both values. In production the first value becomes NaN, corrupting downstream calculations. Error logs show unexpected numbers, leading to wasted debugging time. Automated tests may miss it if they only check the second property. Comment A, B, C, or D with your reasoning. #typescript #programming #codinginterview #backend

🚀 Day 181 of #200DaysOfCoding Today I solved “Minimum Changes To Make Alternating Binary String” on LeetCode. 🔹 Problem: We are given a binary string consisting of 0 and 1. In one operation, we can flip any character (0 → 1 or 1 → 0). The goal is to make the string alternating, meaning no two adjacent characters are the same. Example of alternating strings: 0101, 1010 🔹 Key Insight: An alternating binary string can only have two possible patterns: 1️⃣ 010101... 2️⃣ 101010... So the idea is simple: Count how many changes are needed to convert the string to pattern 1. Count how many changes are needed to convert it to pattern 2. The minimum of the two will be the answer. ⏱ Time Complexity: O(n) 📦 Space Complexity: O(1) Consistent practice is helping me improve my problem-solving and pattern recognition skills every day. #leetcode #coding #programming #cpp #100daysofcode #200daysofcoding #softwaredevelopment

📅 Day 95 of #100DaysOfCode Problem: Path Sum (LeetCode 112) Approach (Recursion / DFS): 1️⃣ Traversed the binary tree using Depth First Search (DFS). 2️⃣ Subtracted the current node value from the target sum. 3️⃣ When reaching a leaf node, checked if remaining sum equals node value. 4️⃣ Recursively checked both left and right subtrees. 5️⃣ Returned true if any root-to-leaf path matched the target sum. #100DaysOfCode #LeetCode #DSA #BinaryTree #DFS #Recursion #ProblemSolving #Cplusplus #CodingChallenge #Programming #DeveloperLife #DailyDSA #KeepLearning #TechCommunity #GrowthMindset #Motivation

📅 Day 88 of #100DaysOfCode Problem: Binary Tree Maximum Path Sum (LeetCode 124) Approach (DFS + Greedy): 1️⃣ Used recursion to compute the maximum gain from left and right subtrees. 2️⃣ Ignored negative contributions using max(0, subtreeSum) — since negative paths reduce the total. 3️⃣ At each node, calculated the current path sum as: left + right + root->val 4️⃣ Updated a global maxSum to track the best path seen so far. 5️⃣ Returned only one side (max(left, right) + root->val) to maintain a valid upward path. #100DaysOfCode #LeetCode #DSA #BinaryTree #DFS #Recursion #DynamicProgramming #ProblemSolving #Cplusplus #CodingChallenge #Programming #DeveloperLife #DailyDSA #KeepLearning #TechCommunity #GrowthMindset #Motivation

🚀 Day 182 of #200DaysOfCoding 📌 Problem: Check if Binary String Has at Most One Segment of Ones (LeetCode 1784) Today’s challenge was about checking whether a binary string contains at most one continuous segment of '1's. 🧠 Problem Understanding We are given a binary string s that starts with 1 and contains only 0 and 1. We need to verify that all 1s appear in one contiguous block. ✔ Valid Examples 111000 110 1000 ❌ Invalid Example 1001 → Here, the segment of 1s breaks and appears again later. 💡 Key Idea If we ever encounter 0 followed by 1, it means a new segment of 1s has started, which violates the condition. ⏱ Complexity Time Complexity: O(n) Space Complexity: O(1) Consistent practice like this is helping me strengthen my problem-solving and data structure skills every day. #Day182 #200DaysOfCoding #LeetCode #DSA #Programming #CodingJourney #ProblemSolving

🚀 Day 185 of #200DaysOfCoding Today I solved a very interesting Dynamic Programming problem: “Find All Possible Stable Binary Arrays”. 🔍 Problem Idea We are given three integers: zero, one, and limit. We need to build binary arrays that: • Contain exactly the given number of 0s and 1s • Do not allow more than limit consecutive 0s or 1s The challenge is to count all possible valid arrays while respecting the constraint on consecutive elements. 💡 Key Learning To solve this efficiently, I used Dynamic Programming with the following idea: Track arrays that end with 0 and arrays that end with 1 Ensure the limit constraint is maintained Subtract invalid states where consecutive elements exceed the allowed limit This approach reduces complexity and handles larger inputs efficiently. ⚙️ Concepts Practiced ✅ Dynamic Programming ✅ State Transition Logic ✅ Handling Constraints on Consecutive Elements ✅ Optimizing DP using mathematical adjustments 📈 What I Learned Today This problem taught me how to carefully design DP states and transitions when additional constraints are involved. It also showed how powerful DP becomes when combined with smart state pruning. Consistency is the key — one step closer to completing the #200DaysOfCoding challenge! 💪 #coding #programming #leetcode #datastructures #algorithms #dynamicprogramming #cpp #learning #softwaredevelopment

📅 Day 98 of #100DaysOfCode Problem: Delete and Earn (LeetCode 740) Approach (Dynamic Programming — House Robber Pattern): 1️⃣ Converted the array into a points array where each index stores total value earned from that number. 2️⃣ Choosing a number deletes its adjacent values (num - 1 and num + 1). 3️⃣ Recognized the pattern similar to the House Robber problem. 4️⃣ At each step, decided whether to take or skip the current value. 5️⃣ Used dynamic programming to maximize total earned points. Many DP problems become easier once you recognize familiar patterns 🧠 #100DaysOfCode #LeetCode #DSA #DynamicProgramming #DP #Arrays #ProblemSolving #Cplusplus #CodingChallenge #Programming #DeveloperLife #DailyDSA #KeepLearning #TechCommunity #GrowthMindset #Motivation