Today marks Day 28 of my Java learning journey — and today, I explored an interesting concept — finding how many times each element appears in a sorted array efficiently. Since the array is already sorted, similar elements are grouped together. This makes it possible to count frequencies in a single traversal, without using any additional data structures. Instead of checking every element repeatedly, we simply move through the array once, count consecutive duplicates, and print their frequency. This approach runs in O(n) time complexity and uses O(1) extra space, making it an elegant and optimized solution. Through this, I understood the importance of utilizing data properties — like sorted order — to simplify and speed up problem-solving. Such techniques are widely used in data analysis, compression algorithms, and frequency-based sorting. Learning this strengthened my understanding of loop control, conditional logic, and how efficient thinking transforms code performance. Every new concept is helping me refine my analytical approach and think like a true problem solver. 💡 #Java #Day28 #Coding #LearningJourney #DataStructures #Arrays #Programming #ProblemSolving #LogicBuilding #JavaLearning #Efficiency #Optimization 

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