Solved LeetCode problem "Max Sum of a Pair With Equal Sum of Digits"

Today, I solved an interesting LeetCode problem called “Max Sum of a Pair With Equal Sum of Digits(https://lnkd.in/gfE37qjM)". It looks simple — until you realize it’s actually two problems cleverly disguised as one. Let’s break it down: Problem 1 — Compute the Digit Sum For each number, we first need its digit sum — a classic number manipulation subproblem. 51 → 5 + 1 = 6   42 → 4 + 2 = 6   This step groups numbers by a common mathematical property — their digit sum. Problem 2 — Find the Maximum Pair Sum in Each Group Once we group numbers by their digit sum, the next challenge is to find two numbers with the same sum of digits that produce the largest total. This now becomes a hash map optimization problem: Use a map to store the largest number seen for each digit sum. For every new number, check if we already have one with the same digit sum. If yes → compute the potential pair sum → update the maximum. Approach Summary Digit Sum Calculation: O(logn) per number Hash Map Lookup: O(1) per operation Overall Time: O(n), efficient and clean Here is the solution Below #LeetCode #JavaScript #Coding

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