Check Binary String for One Segment of Ones

LeetCode Problem 1784: "Check if binary string has atmost one segment of ones": Given a binary string s without leading zeros, return true if s contains at most one contiguous segment of ones. Otherwise, return false. Approach: The idea is simple and straightforward, the given string has no leading zeroes, while looping ensure that after encountering the first segment of ones, no 1 is encountered. If this condition holds, then return True else False. The implementation in Python correctly resolves this problem optimally and efficiently. Time Complexity: O(n) where n is length of given string Space Complexity: constant #LeetCode #Python #Strings #DataStructures #Algorithms #OptimalSolution #ProblemSolving #CompetitiveProgramming #DailyCoding #Programming

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