Optimizing LeetCode's Pow(x, n) with Binary Exponentiation

Day 8 of 30-day Coding Sprint Today’s focus was on a classic problem that teaches you why linear time isn't always good enough when dealing with exponents. Today's progress on LeetCode: 50. Pow(x, n) The Simple Recursive Approach: Multiplying x by itself n times. - Complexity: O(n) time. - The Issue: For large values of n, this hits the stack limit or simply takes too long. The Optimal Strategy: Binary Exponentiation (Divide & Conquer) - The Logic: Use the property (x^n) = (x^n/2)^2. By halving n at each recursive step, we drastically reduce the number of multiplications. The Result: O(log n) time. This turns a billion operations into roughly 30. #30DaysOfCode #DSASprint #LeetCode #JavaScript #Recursion #Math #Consistency

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