#Java21 : 𝗦𝘁𝗿𝗶𝗻𝗴 𝗧𝗲𝗺𝗽𝗹𝗮𝘁𝗲𝘀 - 𝗖𝗹𝗲𝗮𝗿𝗲𝗿 & 𝗘𝗮𝘀𝗶𝗲𝗿 No more messy + or String.format()—just clean, safe, readable strings: Clean ✅ Readable ✅ Bug-free ✅ 𝘚𝘵𝘳𝘪𝘯𝘨 𝘯𝘢𝘮𝘦 = "𝘈𝘭𝘰𝘬"; 𝘚𝘵𝘳𝘪𝘯𝘨 𝘮𝘴𝘨 = "𝘏𝘦𝘭𝘭𝘰, {𝗻𝗮𝗺𝗲} ! 𝘞𝘦𝘭𝘤𝘰𝘮𝘦 𝘵𝘰 𝘑𝘢𝘷𝘢 "; 𝘚𝘺𝘴𝘵𝘦𝘮.𝘰𝘶𝘵.𝘱𝘳𝘪𝘯𝘵𝘭𝘯(𝘮𝘴𝘨); // 𝘏𝘦𝘭𝘭𝘰, 𝘈𝘭𝘰𝘬! 𝘞𝘦𝘭𝘤𝘰𝘮𝘦 𝘵𝘰 𝘑𝘢𝘷𝘢 Java is getting simpler, cleaner, and more powerful day by day! 💡 #Java #Java21 #StringTemplates #CleanCode #DeveloperLife
Java 21 String Templates Simplified
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Day 52/100 Completed ✅ 🚀 Solved LeetCode – Merge Intervals (Java) ⚡ Implemented an interval merging approach by first sorting intervals based on their start times and then traversing them to combine overlapping ranges. 🧠 Used comparison logic to detect overlaps and update interval boundaries, ensuring that all overlapping intervals are merged efficiently. This approach avoids redundant checks and processes the intervals in a single pass after sorting. 💯 Strengthened understanding of interval problems, sorting strategies, and greedy traversal techniques commonly used in real-world scheduling and timeline merging scenarios. Profile: https://lnkd.in/gaJmKdrA #LeetCode #100DaysOfCode #Java #DSA #CodingPractice #ProblemSolving
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🧠 Spring Boot Quick Quiz! Which annotation handles exceptions GLOBALLY across all controllers? A) @ExceptionHandler B) @ControllerAdvice C) @ResponseStatus D) @ErrorHandler 💬 Comment below! #SpringBoot #Java #BackendDevelopment #JavaDeveloper
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Day 59 — LeetCode Progress (Java) Problem: Count the Number of Consistent Strings Required: Given a string allowed and an array of strings words, return the number of consistent strings (strings that contain only characters from allowed). Idea: Use a HashSet for fast lookup to check whether each character in a word is allowed. Approach: Store all characters of allowed in a HashSet. Iterate through each word: Check every character in the word If any character is not in the set, the word is invalid Count all valid (consistent) words. Time Complexity: O(n × m) Space Complexity: O(1) #LeetCode #DSA #Java #HashSet #Strings #Algorithms #CodingJourney #100DaysOfCode
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#day334 of #1001daysofcode problem statement (1009): Complement of Base 10 Integer 💡 Approach: To find the complement of a number, I converted it into binary and flipped every bit (0 → 1 and 1 → 0). After flipping the bits, the resulting binary string was converted back to decimal. Example: 5 → Binary: 101 Complement: 010 → 2 ⏱ Time Complexity: O(log n) 🧠 Space Complexity: O(log n) #1001DaysOfCode #DSA #Java #LeetCode #ProblemSolving Shivam Mahajan #leetcode
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Day 60 - Remove Duplicates from Sorted List Worked on removing duplicate elements from a sorted linked list. Approach: • Traverse the list once • Compare current node with next node • Skip duplicate nodes by adjusting pointers Time Complexity: O(n) Space Complexity: O(1) #Day60 #LeetCode #Java #LinkedList #CodingPractice #DSA #TechJourney
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Ever tried adding two numbers in Java… and it failed? 🤯 I recently hit this: existingValue + proposedValue ❌ Compilation error! Reason? They were not primitives… they were BigDecimal. Fix was simple, but important: existingValue.add(proposedValue) ✔ That’s when it clicked 👇 In financial or precision-based systems, BigDecimal is not just a choice — it’s a necessity. Also learned: Null handling + proper scaling (setScale) can save you from hidden production bugs. Small issue. Big lesson. Have you faced this before? #ProductionIssues #JavaDeveloper #Java #Debugging
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Can you predict the output? 🤔 int x = 5; System.out.println(x++ + ++x); Drop your answer below 👇 I’ll share the explanation in a few hours ⏳ #Java #CodingChallenge #DSA
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Frameworks evolve, but strong Core Java fundamentals still make the biggest difference. Over the years, I’ve seen that maintainable systems are built on solid basics: good object design, multithreading awareness, and clear interface contracts. These fundamentals matter even more in integration-heavy systems, where clean design can save a lot of debugging time later. #Java #CoreJava #SoftwareEngineering #SystemDesign
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