Aditya Singhal’s Post

🚀 Day 60 / 100 – LeetCode Daily Challenge 💻 Problem: Reverse Bits (Bit Manipulation) Today marks Day 60 of my 100-day LeetCode journey, and I tackled the classic Reverse Bitsproblem — a fascinating deep dive into bit-level manipulation and optimization. 🔍 Problem Overview: Given a 32-bit unsigned integer, the task is to reverse its bits. For example, reversing 43261596 (binary: 00000010100101000001111010011100) gives 964176192 (binary: 111001011110000010100101000000). ⚙️ My Approach: I implemented a highly optimized divide and conquer strategy using bit masking and shifting — no loops, no extra memory, just pure bitwise operations. The algorithm swaps bits in stages: first 16-bit halves, then 8-bit chunks, followed by 4-bit, 2-bit, and finally 1-bit swaps. This results in O(1) time complexity and runs in 0 ms, beating 100% of submissions! 📌 Key Insight: Bit manipulation is not just efficient — it’s elegant. By treating the integer as a fixed-width binary string and applying a series of masks and shifts, we can reverse bits in logarithmic steps rather than iterating through all 32 bits. ✅ Result: ✅ Runtime: 0 ms | Beats 100% ✅ Memory: 100% efficient ✅ Test cases passed with flying colors 🧠 Takeaway: This problem reinforced the power of understanding how data is represented at the bit level. Whether you're working on embedded systems, networking protocols, or performance-critical code, bit manipulation is an essential tool in every developer’s toolkit. On to the next challenge! 💪 #LeetCode #100DaysOfCode #CodingChallenge #Java #BitManipulation #ReverseBits #ProblemSolving #Programming #Tech #DeveloperJourney #LearnInPublic #CodeNewbie #SoftwareEngineering #BitwiseOperations #DailyCoding #Algorithms #DataStructures

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Aditya Singhal I applied Different Approach: Take Rightmost but of n using bitwise & operator Then left shift Result by 1 Add rightmost bit using bitwise or operator And then leftshift result Do this for 32 times. It was quite simole though. Yeah but I used a loop🫠

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