Understanding Arrays.sort(s, 0, n, (a, b) -> …) When you see this method, here’s what it actually means: s → the array you’re sorting 0 → the starting index (inclusive) n → the ending index (exclusive) (a, b) → a lambda expression defining how two elements are compared 💡 In simple terms: “Sort only the part of the array from index 0 to n-1 using your custom comparator.” This is extremely useful when handling partial datasets, custom numeric ordering, BigDecimal comparisons, or stable sorting rules. #Java #Programming #Developers #TechLearning
Sorting Arrays in Java with Custom Comparator
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🚀 Code 6 – #50LeetCodeChallenge 🧩 Problem: Search Insert Position Given a sorted array of distinct integers and a target value, return its index if found. If not, return the position where it should be inserted to maintain sorted order. 💡 Approach: Use Binary Search to efficiently locate the target or its correct insertion position in O(log n) time. 📚 Key Takeaway: Binary search is the go-to technique for problems involving sorted arrays, especially when optimal time complexity is required. #LeetCode #Java #Coding #ProblemSolving #BinarySearch #Arrays #Programming
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Understanding arrays is not enough knowing how to operate on them is key. In this short video, I covered: - Traversal (O(n)) - Insertion (O(1) at end, O(n) in middle) - Deletion (O(1) at end, O(n) in middle) - Why shifting elements impacts performance These fundamentals help in choosing the right data structure and writing optimized code. Explore structured DSA in Java roadmap + practice: www.quipoin.com #DSA #Java #Programming #Coding #SoftwareEngineering #DataStructures #Algorithms
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🚀 Day 23 of #50DaysOfCode Solved Daily Temperatures (LeetCode 739) 🌡️ Today’s focus was on mastering the Monotonic Stack concept — one of the most powerful patterns in DSA. Learned how to efficiently find the next greater element by storing indices and resolving them smartly instead of brute force. 💡 Key Learnings: • Stack helps reduce time complexity from O(n²) → O(n) • Always think in terms of “pending answers” • Monotonic stacks are 🔥 for interview questions ✅ Status: Accepted ✔️ ⏱️ Optimized approach implemented Every day getting better at problem-solving and consistency 💪 #DSA #LeetCode #Java #CodingJourney #Consistency #100DaysOfCode #Programming
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🚀 Day 15 of 180 — 3Sum Closest ✅ LeetCode 16 — 3Sum Closest First sort the array. Then fix one element and use two pointers for the remaining two — one at left, one at right. For every triplet I calculate the sum and check how far it is from the target: distance = |target - sum| If this distance is less than my current minimum difference, I update my answer. Moving pointers is simple — if sum is greater than target → move right pointer left if sum is less than target → move left pointer right if sum equals target → that's the closest it can get, return immediately The key thing I made sure — keep tracking the minimum difference throughout and update result whenever a closer sum is found. Day 15 done. 165 to go. 🔥 #180DaysDSA #Day15 #LeetCode #Java #DSA #TwoPointers #Sorting #ThreeSum #DSAJourney #CodingJourney #Programming #DataStructures #Algorithms #ProblemSolving #BuildInPublic #CodeNewbie #LearnToCode #100DaysOfCode #SoftwareDevelopment #Developer #StudentDeveloper #TechCommunity #LinkedInTech #CompetitiveProgramming
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🚀 Code 3 – #50LeetCodeChallenge Problem: 4Sum Given an array of integers and a target value, find all unique quadruplets that sum up to the target. Each element must be used only once, and the solution set should not contain duplicate combinations. 💡 Approach: Sort the array and use nested loops along with a two-pointer technique to find combinations efficiently. Skip duplicate elements to ensure only unique quadruplets are included. 📚 Key Takeaway: Combining sorting with the two-pointer approach helps reduce complexity and is highly effective for solving multi-sum problems like 4Sum. #LeetCode #Java #Coding #ProblemSolving #Arrays #TwoPointers #Programming
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What if a function could call itself to solve a problem? That’s exactly what Recursion is. In this short video, I explained: - What is recursion - Base case (stops execution) - Recursive case (reduces problem size) - Factorial example - Importance of call stack Recursion is widely used in solving complex problems like trees, graphs, and divide-and-conquer algorithms. Explore structured DSA in Java roadmap + practice: www.quipoin.com #DSA #Java #Programming #Coding #SoftwareEngineering #Recursion #InterviewPreparation
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💻 Built a Diamond Pattern in Java using pure logic and nested loops. While practicing DSA fundamentals, I implemented this pattern by understanding how spaces and stars align in each row. This helped me strengthen my control over loops, conditions, and pattern-based problem solving. 📌 Key Learning: Breaking a complex pattern into smaller logical steps makes it much easier to implement. Consistency in solving such problems is what builds strong programming logic. #Java #DSA #Programming #CodingJourney #ProblemSolving #LogicBuilding #Developers #Learning #100DaysOfCode
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🚀 Code 5– #50LeetCodeChallenge 🧩 Problem: Remove Element Given an array and a value val, remove all occurrences of val in-place and return the count of remaining elements. The order of elements can be changed. 💡 Approach: Use a two-pointer technique—one pointer iterates through the array, while the other keeps track of the position to place elements that are not equal to val. 📚 Key Takeaway: In-place modification with two pointers helps achieve O(n) time complexity and O(1) space, making it efficient for array filtering problems. #LeetCode #Java #Coding #ProblemSolving #Arrays #TwoPointers #Programming
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Most developers focus only on speed… but memory usage is equally important. This is where Space Complexity comes in. In this short video, I covered: - What is space complexity - Big O notation for memory - O(1), O(n), O(n²) explained - Why recursion uses extra space Understanding both time and space complexity helps you write efficient and scalable code. Explore structured DSA in Java roadmap + practice: www.quipoin.com #DSA #Java #Programming #Coding #SoftwareEngineering #BigO #InterviewPreparation
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How do you solve problems where you need to try every possible combination? This is where Backtracking comes in. In this short video, I explained: - What is backtracking - How it works (try → explore → undo) - Real-world examples like N-Queens and Sudoku - Importance of pruning Backtracking is a powerful approach for solving complex constraint-based problems. Explore structured DSA in Java roadmap + practice: www.quipoin.com #DSA #Java #Programming #Coding #SoftwareEngineering #Algorithms #InterviewPreparation
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