🧠 Coding Challenge: Merge Sorted Arrays Here’s a simple-looking problem that tests your logic and attention to detail 👇 You are given two sorted arrays: let arr1 = [1, 5, 8, 9] let arr2 = [3, 4, 6, 10] 🎯 Task: Merge these two arrays into a single sorted array. Sounds easy, right? But there’s a catch… 👀 Think about: - How will you compare elements efficiently? - What happens when one array finishes before the other? - Are you sure your loop covers all cases? ⏳ Take a moment and try solving it yourself before scrolling further. 💬 If you get stuck or want to verify your approach, check the answer in the comments! #JavaScript #CodingChallenge #DSA #Programming #WebDevelopment
Merge Two Sorted Arrays in JavaScript
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The new keyword looks simple… but most people use it without knowing what it actually does 👀 That’s exactly where confusion starts. Why does a function suddenly create objects? Where does this point? And how do methods magically appear? 👉 It’s all because of new. In this blog, I’ve explained: What new actually does behind the scenes How constructor functions create objects How objects link to shared methods (prototype) Why everything breaks without new Kept it simple, with step-by-step explanation and examples ✨ 🔗 Read here: https://lnkd.in/dyZwek-x Would love your feedback 🙌 Next: Constructor Functions or this keyword? #javascript #webdevelopment #programming #coding
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🚀 Day 37/128 of My LeetCode Challenge Solved: Search Insert Position on LeetCode 🔹 Problem: Given a sorted array of distinct integers and a target value, return the index if the target exists. Otherwise, return the position where it should be inserted in sorted order. 💡 Approach: Used Binary Search to achieve O(log n) time complexity by repeatedly dividing the search space in half. ✅ Key takeaway: Sometimes the answer isn’t just finding an element — it’s understanding where it belongs when it doesn’t exist. Binary search makes this super efficient. Consistency > perfection. One problem at a time 💯 #LeetCode #128DaysOfCode #CodingChallenge #JavaScript #DSA #BinarySearch #Programming #SoftwareEngineering
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Event Bubbling vs Event Capturing: Mastering DOM Event Propagation Learn the difference between event bubbling and event capturing, when to use each, and how to implement them with clean, production‑ready JavaScript code. This tutorial walks you through concepts, practical examples, and best‑practice patterns. Read the full article 👇 https://lnkd.in/gYXpk-ST #JavaScript #WebDevelopment #Programming #Coding #Tech #EventPropagation #DOMEvents #EventBubbling #EventCapturing #FrontendEngineering #DigitalTransformation #FutureOfWork
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LeetCode Day 2 : Problem 26 (Remove Duplicates from Sorted Array) Just solved my third LeetCode problem. It was "Remove Duplicates from Sorted Array", sounds straightforward, right? But here's what I actually learned: My first instinct was to use .splice() inside a loop. It works, but every splice shifts all elements after it, meaning for a large array you're doing that shift hundreds of times. Slow. I also added .sort() at the top — but the problem already guarantees a sorted array. Sorting again is just wasted work. Always read the constraints. The fix? Two Pointer pattern again. Since duplicates are always next to each other in a sorted array, just compare each element with the previous one. One pass, no splicing, no sorting. Three problems in. The Two Pointer pattern has shown up in all three. Same idea, slightly different condition each time. The real lesson? Before writing code, read the constraints carefully. They often tell you exactly what you don't need to do. #DSA #LeetCode #JavaScript #CodingJourney #Programming
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Turning concepts into clarity 💡 Exploring Arrays & Array Functions with a developer-style visual inspired by VS Code. Simple, structured, and beginner-friendly — because good code starts with strong fundamentals. #Programming #JavaScript #Coding #WebDevelopment #Learning
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Quick one for the developers in my network. CSS has methods most people either forget about or never got properly introduced to. And they show up constantly once you know what to look for. #CSS #WebDevelopment #FrontendDevelopment #Programming #TechEducation #LearnToCode #Developer #WebDesign #CodingTips #SoftwareEngineering
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📌 async/await A modern syntax built on top of Promises Allows writing asynchronous code in a synchronous style await pauses execution until the Promise is resolved Simplifies error handling using try/catch 👉 Use case: API requests, asynchronous workflows #JavaScript #AsyncAwait #CleanCode #Programming #WebDevelopment
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Here is the final part of our weekly series on object Destructuring. Functions, Rest and Pro Patterns. If our content has been of great help to you. Drop a comment or a suggestion on how we can do better. #programming #javascript
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𝐈𝐧 𝐉𝐚𝐯𝐚𝐒𝐜𝐫𝐢𝐩𝐭, 𝐟𝐮𝐧𝐜𝐭𝐢𝐨𝐧𝐬 𝐚𝐫𝐞 𝐧𝐨𝐭 𝐣𝐮𝐬𝐭 𝐟𝐮𝐧𝐜𝐭𝐢𝐨𝐧𝐬… They’re values. You can: • Pass them as arguments • Return them from other functions • Assign them to variables This is what makes patterns like callbacks, closures, and higher-order functions possible. But many developers use these without fully understanding them. We’ve broken it down with simple examples in our latest blog. Read here: https://lnkd.in/gEWNYg_p #JavaScript #Programming #WebDevelopment
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LeetCode Day 3 : Problem 189 (Rotate Array) Just solved another LeetCode problem. It was "Rotate Array", sounds simple, right? But here's what I actually learned: My first solution used pop() and unshift() in a loop. It worked but was O(n×k), every unshift shifts the entire array one step, and I was doing it k times. On a large array that's painfully slow. I forgot to handle the case where k is larger than the array length. Rotating a 3 element array by 6 steps is the same as rotating by 0. One line fix, k = k % nums.length. Always think about edge cases before submitting. The optimal fix? The Reverse Trick. Reverse the entire array, then reverse the first k elements, then reverse the rest. Three reverses. One pass. O(n) time, O(1) space. Hard to believe it works until you trace through it yourself. Six problems in. The pattern is clear, there is always a brute force solution and a clever one. The clever one usually involves looking at the problem from a completely different angle. The real lesson? If your solution involves a loop inside a loop, always ask yourself if there is a smarter way. #DSA #LeetCode #JavaScript #CodingJourney #Programming
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